0.5x^2+0.6x=0.8

Solution for 0.5x^2+0.6x=0.8 equation:

0.5x^2+0.6x=0.8

We move all terms to the left:

0.5x^2+0.6x-(0.8)=0

We add all the numbers together, and all the variables

0.5x^2+0.6x-0.8=0

a = 0.5; b = 0.6; c = -0.8;
Δ = b2-4ac
Δ = 0.62-4·0.5·(-0.8)
Δ = 1.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.6)-\sqrt{1.96}}{2*0.5}=\frac{-0.6-\sqrt{1.96}}{1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.6)+\sqrt{1.96}}{2*0.5}=\frac{-0.6+\sqrt{1.96}}{1}
$